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Same color for all the Point in a Scatter Plot


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Ok, my first question was not good.

I would like to draw a scatter plot, with many points (X,Y). But when I use

the Scatter graph of ChartFX, I get red and blue points, which is not what I

want. I only want a simple scatter plot with as many points as I give in the

list to the plot.

What am I doing wrong?

Thx,

Oli

"Olivier" <olivier.voyer@cyme.com> wrote in message

news:iw7PRiztGHA.2444@webserver3.softwarefx.com...

> Hello,

>

> I draw a scatter plot, but when I 2 points have the same X-value, one

> point is painted in red and the other in blue. I would like to have all

> the points painted in red. How can I do that?

>

> Thank you very much in advance :)

>

> Olivier

>

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Thanks for your answer,

However, I have another problem. When 2 points in a graph have the same

X-coordinate, these two points are not at the same vertical position as I

would expect it. In fact, they are drawn as if they had two different

X-coordinates. So, there are two x-coordinates that have the same label. For

example:

* *

*

(5,10) (6,12) (5,12)

But I would expect:

* *

*

(5,10) (6,12)

(5,12)

How can I correct this problem?

Thank you,

Olivier Voyer

CYME International

"SoftwareFX Support" <noreply@softwarefx.com> wrote in message

news:kgGsqh9tGHA.2276@webserver3.softwarefx.com...

> Seems that you are creating 2 series and that's the reason you are getting

> two colors.

>

> You have several options here:

>

> 1) Create one series only

> 2) Assign: chart.Series[1].Color = chart.Series[0].Color

>

> --

> Francisco Padron

> www.chartfx.com

>

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You must be passing your data incorrectly. When you pass the data as 

specified you will get the two point in the same X-Coordinate.

It is important to notice X-Values and labels are NOT the same, X-Values are

numeric and control the position of the pint in the x-axis (in charts that

support X-values such as Line, Scatter, Area), Labels are just strings used

to label the axis and have no influence in the position of the point.

Please attach the code section containing the way you are passing the data

to this chart.

--

Francisco Padron

www.chartfx.com

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Yes, you must be right. Here is my code:

==============================

object[] allArrays = new object[2];

double[] myArray = new double[lstMyList.Count];

string[] labelArray = new string[lstMyList.Count];

myArray [0] = 5;

myArray [1] = 10;

myArray [2] = 15;

labelArray[0] = "3";

labelArray[1] = "5";

labelArray[2] = "3";

allArrays[0] = myArray ; // Y-Value

allArrays[1] = labelArray; // (Labels)

ListProvider lstProvider = new ListProvider(allArrays);

base.DataSourceSettings.DataSource = lstProvider;

==============================

Thx,

Olivier

"SoftwareFX Support" <noreply@softwarefx.com> wrote in message

news:X3MQSfJuGHA.2444@webserver3.softwarefx.com...

> You must be passing your data incorrectly. When you pass the data as

> specified you will get the two point in the same X-Coordinate.

>

> It is important to notice X-Values and labels are NOT the same, X-Values

> are numeric and control the position of the pint in the x-axis (in charts

> that support X-values such as Line, Scatter, Area), Labels are just

> strings used to label the axis and have no influence in the position of

> the point.

>

> Please attach the code section containing the way you are passing the data

> to this chart.

>

> --

> Francisco Padron

> www.chartfx.com

>

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Yes. There is no X-Value. Your labels are strings !

You need to change this as follows:

double[] xValues = new double[lstMyList.Count];

// Initialize array

...

base.DataType[0] = DataType.Value;

base.DataType[1] = DataType.XValue;

ListProvider lstProvider = new ListProvider(allArrays);

base.DataSourceSettings.DataSource = lstProvider;

--

Francisco Padron

www.chartfx.com

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Yes. There is no X-Value. Your labels are strings !

You need to change this as follows:

double[] xValues = new double[lstMyList.Count];

// Initialize array

...

base.DataType[0] = DataType.Value;

base.DataType[1] = DataType.XValue;

ListProvider lstProvider = new ListProvider(allArrays);

base.DataSourceSettings.DataSource = lstProvider;

--

Francisco Padron

www.chartfx.com

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Thx for your answer :)

Unfortunately, that didn't work:

base.DataType[0] = DataType.Value;

base.DataType[1] = DataType.XValue;

"DataType" is not a property of the "base" class (which is derived from the

"Chart" class) and the compiler doesn't recognize "DataType.Value" and

"DataType.XValue".

Can you help me again please?

Olivier

CYME International T&D

Errors: The name 'DataType' does not exist in the current context

"SoftwareFX Support" <noreply@softwarefx.com> wrote in message

news:LOwUJojuGHA.2276@webserver3.softwarefx.com...

> Yes. There is no X-Value. Your labels are strings !

>

> You need to change this as follows:

>

> double[] xValues = new double[lstMyList.Count];

>

> // Initialize array

>

> ...

>

> base.DataType[0] = DataType.Value;

> base.DataType[1] = DataType.XValue;

> ListProvider lstProvider = new ListProvider(allArrays);

> base.DataSourceSettings.DataSource = lstProvider;

>

>

> --

> Francisco Padron

> www.chartfx.com

>

>

>

>

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Hi again. Thank you for your patience :)

Version of ChartFX : Chart FX for Visual Studio 2005

Olivier

"SoftwareFX Support" <noreply@softwarefx.com> wrote in message

news:N5NC25luGHA.1228@webserver3.softwarefx.com...

>I should have asked this in the beginning: What version of Chart FX are you

>using ?

>

> --

> Francisco Padron

> www.chartfx.com

>

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Ok. That explains it.

The code is:

object[] allArrays = new object[2];

double[] myArray = new double[3];

double[] xValues = new double[3];

myArray [0] = 5;

myArray [1] = 10;

myArray [2] = 15;

xValues[0] = 3;

xValues[1] = 5;

xValues[2] = 3;

allArrays[0] = myArray ; // Y-Value

allArrays[1] = xValues; // X-Values

chart1.DataSourceSettings.Fields.Add(new

FieldMap("Field1",FieldUsage.Value));

chart1.DataSourceSettings.Fields.Add(new

FieldMap("Field2",FieldUsage.XValue));

ListProvider lstProvider = new ListProvider(allArrays);

chart1.DataSourceSettings.DataSource = lstProvider;

To avoid the same confusion and expedite our responses please post to the

appropriate newsgroup: chartfx.vs2005.WinForms

--

Francisco Padron

www.chartfx.com

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Ok thank you very much!

Have a nice day,

Olivier

"SoftwareFX Support" <noreply@softwarefx.com> wrote in message

news:w8IvF5vuGHA.2136@webserver3.softwarefx.com...

> Ok. That explains it.

>

> The code is:

>

> object[] allArrays = new object[2];

>

> double[] myArray = new double[3];

>

> double[] xValues = new double[3];

>

> myArray [0] = 5;

>

> myArray [1] = 10;

>

> myArray [2] = 15;

>

> xValues[0] = 3;

>

> xValues[1] = 5;

>

> xValues[2] = 3;

>

> allArrays[0] = myArray ; // Y-Value

>

> allArrays[1] = xValues; // X-Values

>

> chart1.DataSourceSettings.Fields.Add(new

> FieldMap("Field1",FieldUsage.Value));

>

> chart1.DataSourceSettings.Fields.Add(new

> FieldMap("Field2",FieldUsage.XValue));

>

> ListProvider lstProvider = new ListProvider(allArrays);

>

> chart1.DataSourceSettings.DataSource = lstProvider;

>

>

> To avoid the same confusion and expedite our responses please post to the

> appropriate newsgroup: chartfx.vs2005.WinForms

>

> --

> Francisco Padron

> www.chartfx.com

>

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